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inverse trigonometric functions | trigonometric functions #maths #shorts #yt

Inverse Trigonometric Functions: Prove that tan⁻¹ [(3a^2 - x^3)/(a^3 - 3ax^2)] = 3 tan⁻¹ x/a

Inverse Trigonometric Functions : Prove that: tan⁻¹ [√ {(1+x^2) -1 }/x] = 1/2 (tan⁻¹ x)

Inverse Laplace Transform Using the Table #math #engineering