We are concerned with solving polynomial equations over rings. More precisely, given a commutative domain A with 1 and a polynomial equation an tn + . . . + a₀ = 0 with coefficients ai in A, our ...

In particular, it follows that for almost every 0 < θ < 1, the quadratic Pθ has a Siegel disk whose boundary is a Jordan curve passing through the critical point of Pθ. By standard renormalization ...

Researchers have found a new way to solve high-degree polynomial equations, previously thought impossible for 200 years. This math breakthrough reopens algebra.

Polynomial Equations Formula Example of a polynomial equation is: 2x2 + 3x + 1 = 0, where 2x2 + 3x + 1 is basically a polynomial expression which has been set equal to zero, to form a polynomial ...

The two solutions to this quadratic equation are 2 – u and 2 + u, or –1 and 5. In other words, this parabola intersects the x -axis when x = –1 and x = 5.

But some roots are more complex. Take the quadratic polynomial x 2 + 1. Such an expression is only equal to zero when x 2 is equal to –1, but on its face this seems impossible.