If a quadratic ... The equation factorises to give \((x – 3)(x – 3) = 0\) so there is just one solution to the equation, \( x = 3\). The graph of \(y = x^2 - 6x + 9 \) touches the x-axis ...

If a quadratic equation can be factorised, the factors can be used to find the roots of the equation. The equation factorises to give \((x + 3) (x - 2) = 0 \) so the solutions to the equation \(x ...